A 5.0 g ice cube at -10 C is in a rigid, sealed contain

A 5.0 g ice cube at -10 C is in a rigid, sealed container from which all the air has been evacuated. The specific heat at constant volume of steam is 1500 J/kgK. How much heat is required to change this ice cube into steam at 170 C ?

Solution

Q = m*c*T
Q = m*Lf
Q = m*Lv

Those are the 3 equations you need.

Lv is the heat of vaporization.
Lf is the heat of fusion.
c is the specific heat per substance.

At the end, you\’re going to add up all the different Q\’s we obtain to get the total E required for this system
1st step: The ice needs to reach 0°C
Q1 = (0.005)(specific heat of ice)(0°C – (-10°C)
Q1 = (0.005)(2030)(10°C) =101.5J

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